The surface area of sphere t is 452.16 units squared. the surface area of sphere x is 1808.64 units squared. how many times larger is the radius of sphere x than the radius of sphere t?

the radius of sphere X is 2 times larger than the radius of sphere T

Step-by-step explanation:

Given

Surface area of sphere, T =452.16

Surface area of sphere, X= 1808.64

how many times larger is the radius of sphere X than the radius of sphere T?

Finding radius of both spheres:

Surface area of sphere is given as

A=4πr^2

Now putting value of Ta=452.16 in above formula

452.16=4πrt^2

rt^2=452.16/4π

rt^2=35.98

Taking square root on both sides

rt=5.99

Now putting value of Xa=1808.64 in above formula

1808.64=4πrx^2

rx^2=1808.64/4π

rx^2=143.92

Taking square root on both sides

rx=11.99

Comparing radius of sphere X and the radius of sphere T

rx/rt=11.99/5.99

      = 2.00

rx=2(rt)

Hence the radius of sphere X is 2 times larger than the radius of sphere T!

The answer is:

The radius of the  sphere X is 2 times larger than the radius of the sphere T

To solve the problem, we need to find the radius of both spheres using the following formula:

Where,

Area, is the area of the circle.

r, is the radius of the circle.

So,

We are given:

Now, calculating we have:

For the sphere X,

For the sphere T,

Then, dividing the radius of the X sphere by the  T sphere to know the ratio (between their radius), we have:

Hence, we have the radius of the sphere X is 2 times larger than the radius of the sphere T.

Have a nice day!

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

17.08

correct me if i am wrong.