If the modulus is 4 and the real part is 2.0, what is the imaginary part?

ANSWER

EXPLANATION

We we're given that, the real part of the complex number is 2.

Let the imaginary part be y.

Then the complex number is

Also, we have that, the modulus is 4.

The modulus is given by the formula;

This implies that,

We square both sides to obtain;

Therefore the complex part is

$35.59 in pounds

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92