Acircular swimming pool has a radius of 15 ft. there is a path all around that pool that is three feet wide. what is the circumference of the outer edge of the path around the pool? use 3.14 for pi 56.52 ft 94.20 ft 113.04 ft 114.04 ft

the circumference of the outer edge of the path around the pool is 113.04 ft

Step-by-step explanation:

Hello, I think I can help you with this

the circumference is given by:

S=2π*r

where, S is the length of the circumference,π=3.14159.., r= radius

Step one

define the radius

the total radius of the pool and the path is

radius=15 ft + 3 ft

radius=18 ft

Step two

π=3.14

radius=18 ft

put the values into the equation

S=2π*r

S=2*3.14*18 ft

S=113.04 ft

the circumference of the outer edge of the path around the pool is 113.04 ft

I hope it helps, Have a nice day.

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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step-by-step explanation:

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