Asurvey of pet owners found that on average, they spend $1,225 annually per pet, with a standard deviation of $275. between which two amounts would you expect 95% of the survey’s respondents to spend annually per pet if the sample is approximately normal and comes from a normally distributed population?

Between 1489 to 2309 the two amounts between which, 95% of the surveys respondents to spend annually per pet if the same sample is approximately normal distributed population.

Step-by-step explanation:

Given : A survey of pet owners found that on average, they spend $1,225 annually per pet, with a standard deviation of $275.

To find : Between which two amounts would you expect 95% of the survey’s respondents to spend annually per pet if the sample is approximately normal and comes from a normally distributed population?

Solution :

Mean expenditure on pets is

Standard deviation is

We know that, z score at 95% is 1.96.

Applying z score formula,

The two amounts between which, 95% of the surveys respondents to spend annually per pet if the same sample is approximately normal distributed population is given by,

Therefore, Between 1489 to 2309 the two amounts between which, 95% of the surveys respondents to spend annually per pet if the same sample is approximately normal distributed population.

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b