Idon’t know how to graph two equations that 2w+2l=228 and l=w+42 and calculate the w and l.

Solve for w and l by using the system of equations.

2l=-2w+228

l=w+42

Substitute w+42 for l in the first equation.

2(w+42)=-2w+228

2w+84=-2w+228

4w=144

w=36

Now substitute 36 for w in any equation to get l=78.

To graph the equations, first make them equal l.

l=-w+114 and l=w+42 are your equations. You ca plug in values for w to plot points on the graph.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b