Suppose that there are two types of tickets to a show: advance and same-day. advance tickets cost $25 and same-day tickets cost $35. for one performance, there were 45 tickets sold in all, and the total amount paid for them was $1375 . how many tickets of each type were sold?

For this case we propose a system of equations:

x: Variable representing the anticipated tickets

y: Variable representing the same day tickets

So:

We clear x from the first equation:

We substitute in the second equation:

We look for the value of x:

Thus, 20 of anticipated type and 25 of same day type were sold.

20 of anticipated type and 25 of same day type were sold.

20 advance tickets and 25 same-day tickets.

Step-by-step explanation:

Set up a system of equations.

Let be "a" the number of advance tickets and "s" the number of same-day tickets.

Then:

You can use the Elimination method. Multiply the second equation by -25, then add both equations and solve for "s":

Substitute into an original equation and solve for "a":

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336