Urgent will give brainliest determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.

(5sqrt(2), 45 deg)

(-5sqrt(2), 225 deg)

Step-by-step explanation:

(x,y)=(5,5)

So theta=arctan(5/5)=arctan(1)=45 degrees

Now r! r=sqrt(x^2+y^2)=sqrt(5^2+5^2)=sqrt(50)=sqrt(25)sqrt(2)=5sqrt(2)

So one polar point is (5sqrt(2) , 45 degrees)

Now if we do 180+45=225 degrees... this puts us in the 3rd quadrant... to get back to quadrant 1 we just take the opposite of our r

so another point is (-5sqrt(2) , 225 degrees)

a) 15/7

step-by-step explanation:

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).