11. 10ac × 6ab × (–2bc) = ? a. 14a2b2c2 b. 2a + 2b + 2c + 14 c. –120a2b2c2 d. 2a + 2b +2c – 120

C. –120a2b2c2

Step-by-step explanation:

We'll just the multiplications one at a time...

10ac × 6ab × (–2bc) = 60a²bc * (-2bc)  (multiplying 10ac × 6ab)

60a²bc * (-2bc)  = -120a²b²c²

We just have to multiply the numbers together (like 10 and 6),

then all similar letters together (like ac * ab = a²bc).  If a letter is already present (like a in this  example), then we add up its powers a * a = a², a² * a would be a³ and so on).  If the letter is not present (like 'b' in 'ac', we suppose it's there as b^0 which is equal to 1)... so we still add up its exponent (power)... so it makes b^0 * b = b

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation:

answer: idk

step-by-step explanation: