Aparallelogram whose vertices have coordinates r(1, -1), s(6, 1), t(8, 5), and u(3, 3) has a shorter diagonal of . 5 √(13) √(97)

Step-by-step explanation:

The given parallelogram has vertices R(1, -1), S(6, 1), T(8, 5), and U(3, 3) .

Recall the distance formula;

We use the distance formula to determine the length of the diagonals.

For diagonal R(1,-1) and T(8,5), We have;

For the diagonal S(6,1) U(3,3)

Therefore the shorter diagonal is:

the 3rd on is correct

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: