Solve the following system of equations 2x + y = 3 x = 2y - 1

x = 1 , y = 1

Step-by-step explanation:

Solve the following system:

{2 x + y = 3 | (equation 1)

x = 2 y - 1 | (equation 2)

Express the system in standard form:

{2 x + y = 3 | (equation 1)

x - 2 y = -1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 3 | (equation 1)

0 x - (5 y)/2 = (-5)/2 | (equation 2)

Multiply equation 2 by -2/5:

{2 x + y = 3 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 2 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

 {x = 1 , y = 1

gaddgad

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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