Mathematics, 22.06.2019 13:20 dianelys3083p5spb5

Determine whether the point (1, 5) is a solution to the system of equations. explain your reasoning in complete sentences. g(x)=3x+2 f(x)=(x-1)+1

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Answer from: alex1975

I think it’s G(x)=3x+2

Answer from: olson1312

(1, 5) is not the solution.

Step-by-step explanation:

As we know the solution to a system of equations is defined by the point of intersection or common points of the given equations.

In this graph the point of intersection is given as (0,2) so the solution of the system of the equations will be the same point (0,2).

Therefore, (1,5) is not the solution to the system of equation.

Answer from: janayshas84

(1,5) is not a solution to the system of equations

Step-by-step explanation:

To find the point (1, 5) is a solution to the system of equations.

We look at the intersection of both graphs given

Both graphs intersects at (0,2)

Intersection of two graphs is the solution of system of equations

Two graphs intersects at (0,2). so (0,2) is the solution of system of equations

(1,5) is not a solution to the system of equations

Answer from: allimaycatp8qgaq

Step-by-step explanation:

We are given that two equations

y= 3x+2

$y=\mid{x-1}\mid+1$

We have to check point (1,5) is a solution of given system of equations.

If at point (1,5) ,the two equations have same value then the point is a solution of system of equations.

Substitute x=1 then we get

y=3(1)+2=5

$y=\mid{1-1}\mid+1=1$

If we are substituting x=1 then equation give value of y =5 but second equation does not give 5 .Hence , the point (1,5) is not the solution to the system of equation.Because given point does not satisfied the second equation.

Answer from: boo2023

According to your text first equation is
y = 3x+2
second equation is
y = Ix-1I + 1

Definition of our absolute value Ix-1I is
1) we take x-1 with condition x-1≥0 => x≥1
2) we take -(x-1) = -x+1 with x<1

Let's form the first system with condition x≥1
y= 3x+2 and y=x-1+1=> y=x
If the left sides of the equations are equal, than the right sides are equal too
3x+2=x => 3x-x=-2 => 2x=-2 => x=-1
This solution we can't accept because it does not meet the condition
x≥1
Lets's form the second system with condition x<1
y=3x+2 and y= -x+1+1 =. y = -x+2
In the same way as previous the right sides are equal =>
3x+2=-x+2 => 3x+x = +2-2 => 4x=0 => x=0
We accept this solution bacause its meet with condition x<1
When we replace this solution in equation y=3x+2 we got
y=3*0+2=2 Only one solution is (x,y) = (0,2)
Good luck

Answer from: muncyemily

In this case the two equations describe lines that intersect at one particular point. Clearly this point is on both lines, and therefore its coordinates (x, y) will satisfy the equation of either line. Thus the pair (x, y) is the one and only solution to the system of equations. since (1,5) is not an intersection of the two lines then it is not a solution to the systems of equation

Answer from: offensiveneedle

The solution to any system graphically can be found where the 2 graphs intersect. These two graphs intersect at the point (0, 2).

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