Suppose the cells of a tumor are idealized as spheres each with a radius of 5 muμm ​(micrometers). the number of cells has a doubling time of 35 days. approximately how long will it take a single cell to grow into a​ multi-celled spherical tumor with a volume of 0.8 cm^3 ​(1 cm=​10,000 μ​m)? assume that the tumor spheres are tightly packed.

1st part is 64,000,000

2nd part 500,000

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

divide the numbers

step-by-step explanation: