i dont quite get the question but...
i guess this is how it is.
Take the mirror image of∆ABC Through the a line through the point y=3.
The new ∆ABC would have point C=(4,2)
Now shifting the ∆ABC one unit (i.e. 2 acc. to the graph as scale is 1 unit =2) towards right ( or adding 2 to the x coordinates of ∆ABC)
We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).
This coordinate is the same coordinates of ∆A"B"C".
Hope it helps...
To describe a sequence of transformations that maps triangle ABC onto triangle A"B"C", a student starts with a reflection over the x-axis. The student student complete the sequence of transformations to map triangle ABC to triangle A"B"C" is by translating the figure 2 units to the right. Translate the figure 6 units up.
Not so sure though... ask if you have anything else :D
To map triangle ABC onto triangle A''B''C'', we need to observe carefully the graph.
If you draw the libe y = 3, you would notice that triangle A''B''C'' is a reflection of the original triangle across y = 3, because the figure has the same shape and size, but reflected as a mirror, where the mirror is at y = 3.
Then, we move the triangle 2 units rightwards to map ABC onto A''B''C''.
Therefore, the sequence of transformations areReflection across y = 3.Translation rightwards, 2 units