20 if (08.02 mc) a of is : y = 6x − 4 y = 5x − 3 a: in ,of .y-on to . (6 ) b: is to of ? (4 )

A

The first equation has slope 6 and y intercept -4.  I'd plot y intercept (0,-4) and (1,2), and connect the dots and extend for the first line.

The second equation has slope 5 and y intercept -3.  I'd plot y intercept (0,-3) and (1,2), and connect the dots and extend for the second line.

We stumbled on the solution, both lines contain (1,2)

B

I don't like the graphing.  This is algebra, not connect the dots.

We have two equations for y, we equate them to find the x where they meet.

6x - 4 = 5x - 3

6x - 5x = -3 + 4

x = 1

y = 6(1) - 4 = 2

Check:  y = 5(1) - 3 = 2, good

(1, 2)

1/800 is the right answer

3x + 4y -25 =0 represents the amount of change sianna should recieve