In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. the article "modeling of simultaneously continuous and stochastic construction activities for simulation" (j. of construction engr. and mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value 8.46 min and standard deviation .913 min for the rv x 5 truck haul time. a. what is the probability that haul time will be at least 10 min? will exceed 10 min? b. what is the probability that haul time will exceed 15 min? c. what is the probability that haul time will be between 8 and 10 min? d. what value c is such that 98% of all haul times are in the interval from 8.46 2 c to 8.46 1 c? e. if four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer is because 4×10=40

and 98×4= is 392

40,392

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)