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Mathematics, 01.07.2019 23:20 bri2008

The path bold r left parenthesis t right parenthesisr(t)equals=left parenthesis t right parenthesis bold i plus left parenthesis 4 t squared minus 1 right parenthesis bold j(t) i+4t2βˆ’1 j describes motion on the parabola y equals 4 x squared minus 1y=4x2βˆ’1. find the particle's velocity and acceleration vectors at t equals 5t=5, and sketch them as vectors on the curve.

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