Abaseball field is in a shape of a square. the distance between each pair of bases along the edge of the square is 90 feet. what is the distance between home plate and second bass?

Step-by-step explanation:

We want to find the length of the square's diagonal.  Since the square has right angles, we can use Pythagorean theorem.

c² = a² + b²

x² = 90² + 90²

x = 90√2

x ≈ 127.3 feet

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.