Which set of three numbers could be the side lengths of an triangle 3,5,9 2,4,6 2,4,8 3,5,7

3,5,7

Step-by-step explanation:

to find which set it is you have to add the first too like this

3+5 >7 if greater than 7 move on too this

5+7>3 if greater move on to this

3+7>5 if greater that means it is a set you can use

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer is 12345678900987654321234567890987654321

step-by-step explanation: