An vulture is perched 40 ft up in a tree and looks down at an angle of depression of a 35? angle and spots roadkill. how far is the roadkill from the vulture? round to the nearest tenth

69.7 ft

Step-by-step explanation:

we know that

The function sine of angle of 35 degrees is equal to divide the opposite side to the angle of 35 degrees (the height of the vulture in a tree) by the hypotenuse ( the distance from the vulture to the roadkill)

Let

z > the distance from the vulture to the roadkill

sin(35°)=40/z

z=40/sin(35°)=69.7 ft

69.7 feet.

Step-by-step explanation:

Let x represent the distance between vulture and roadkill.

We have been given that a vulture is perched 40 ft up in a tree and looks down at an angle of depression of a 35 and spots roadkill.

We can see from the attachment that vulture, roadkill and angle of depression  forms a right triangle with respect to ground, where, x is hypotenuse and 40 ft is opposite side.

Therefore, the roadkill is 69.7 feet away from the vulture.

answer: i wpould go with c

step-by-step explanation:

sorry i got nothing

step-by-step explanation: