Mathematics, 10.07.2019 19:20 AdoNice
The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?
Answers: 1
![2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5](/tpl/images/0074/3382/14616.png)
Equation 1![2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0](/tpl/images/0074/3382/21b12.png)
, we can say:
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The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?...
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