What are the zeroes of f(x) = x2 - 2x - 3?
x= -3,1
x= -3, -1
x= 3,1
x=3, -1

{-1, 3}

Step-by-step explanation:

Please use " ^ " to denote exponentiation:   f(x) = x^2 - 2x - 3.

To find the zeros of this quadratic, set it equal to zero first:

f(x) = x^2 - 2x - 3 = 0.

Now factor this result:  (x - 3)(x + 1) = 0.

The zeros are {-1, 3}

22 dimes and 9 nickels

step-by-step explanation: