If r(x) = 2x - 5 and g(x) = x2 - 4x - 8, find (f + g(%).
o a (f+9)(x) = x2 - 2x-3
o b. (f+g)(x) = x2 - 2x-13
o c. (*+ g)(x) = 3x2 - 4x- 13
o d. (f+ g)(x) = x2 + 2x-3
c
previous

OB. (f+g)(x) = x^2-2x-13

Step-by-step explanation:

Given

f(x) = 2x-5

and

g(x) = x^2-4x-8

We have to find (f+g)(x)

So,

(f+g)(x) = f(x) + g(x)

= 2x-5 + (x^2-4x-8)

= 2x-5+x^2-4x-8

= x^2+2x-4x-5-8

=x^2-2x-13

Therefore, Option B is correct ..

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4