Yvaries inversely with x. when y = 9.6, x = 12. what is the value of k, the constant of inverse variation?
round to the nearest tenth, if necessary.
-y varies inversely with x, and k (the constant of variation) = 5.6. what is the value of y when x = 4?
round to the nearest tenth, if necessary

Question 1:

For this case we have an equation of the form:

Where,

Then, substituting values we have:

From here, we clear the value of k.

We have then:

the constant of inverse variation is:

Question 2:

For this case we have:

Where,

Then, substituting the value of the constant we have:

We now substitute the value of x:

 the value of y when x = 4 is:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1