Aball is launched into the air from below a cliff, such that after t seconds its height above the cliff top is hmetres, and is given by the equation
h =  − 4.9t^2 + 19.6t − 12.6.
calculate, to the nearest metre, the maximum height the ball achieves above the cliff top.

7 meters

Step-by-step explanation:

In order to find the answer we need to calculate the first derivative of the function as follows:

Now, for obtaining the time 't' when the ball reaches the maximum height:

Finally, we use the original equation for determining the height after 2 seconds:

In conclusion, the maximum height above the cliff top is 7 meters.

answer;

the correct answer

just use google you beautiful person.

have a nice day < 3