Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) the solution is

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

Now, we can say that m>n because m and n are positive integers.

For n=1,

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

Therefore the smallest positive integer solution to the given system of congruences is 30.

0lz try yourself sorry for not answering

the correct answer is b.

this is because an open circle means < or > & since the line goes left it is < -3.

the next one has a filled circle so it can only be ≥ or ≤ and since the line goes right from 1 it is ≥ 1

hope that