Suppose a revenue function is given by: r ( q ) = − q 3 + 140 q where q is thousands of units and r ( q ) is thousands of dollars. for what value of q is revenue maximized. round your answer to the nearest tenth (one decimal place). q = incorrect thousand units

At q=6.8 the revenue is maximum. So, q=6.8 thousand units.

Step-by-step explanation:

The revenue function is

where q is thousands of units and R ( q ) is thousands of dollars.

We need to find for what value of q is revenue maximized.

Differentiate the function with respect to q.

Equate R'(q)=0, to find the critical values.

Divide both sides by 3.

Taking square root both the sides.

Find double derivative of the function.

For q=-6.8, R''(q)>0 and q=6.8, R''(q)<0. So at q=6.8 revenue is maximum.

At q=6.8 the revenue is maximum. So, q=6.8 thousand units.

you would need to know all the numbers that are on there

step-by-step explanation:

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (