Assume that the heights of females in a certain village are normally distributed with a mean of 69 in. and standard deviation of 33 in. what percent of these females are between 6060 in. and 78 in. tall?

21.28%

Step-by-step explanation:

Given : Mean height of females =

Standard deviation :

Let X be a random variable that represents the heights of females in village .

We assume that that the heights of females in a certain village are normally distributed .

Z-score :

For x = 60 in.

For x = 78 in.

Now by using standard normal distribution table , the probability that females are between 60 in. and 78 in. tall :-

Hence, the percent of these females are between 60 in. and 78 in. tall =21.28%

astronomers is your final answer! : )

answer: 10 turtles

step-by-step explanation: as turtles have four legs so 4.10=40 therefore birds are 4 which sue counted