Container 1 has 8 items, 3 of which are defective. container 2 has 5 items, 2 of which are defective. if one item is drawn from each container, what is the probability that only one of the items is defective?

The required probability is

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is

The probability of obtaining a good item from container 1 is

The probability of obtaining a defective item from container 2 is

The probability of obtaining a good item from container 2 is

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

i think is g(1)=-1.

hope that i can