Arectangular steel plate with dimensions of 40.0 cm × 30.0 cm is heated from 14.0°c to 164.0°c. what is its change in area? (coefficient of linear expansion for steel is 11 × 10−6/c°.)

1.98 × 10⁻⁴ meter²

Step-by-step explanation:

A rectangular steel plate having dimensions of 40.0 cm × 30.0 cm is heated from 14.0°C to 164°C.

We have to find the change in its area.

Since formula of Area thermal expansion is

Where = Area thermal expansion coefficient.

            A = Area of the object

            ΔA = change in area

            ΔT = change in temperature.

By replacing the values in the formula.

11 × 10⁻⁶ =

= 132 × 150 × 10⁻⁸

= 19800 × 10⁻⁸

= 1.98 × 10⁻⁴ meter²

7

step-by-step explanation:

the answer would be 7

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.