The base of a right prism is a rhombus with diagonals of 6 and 8. if the altitude of the prism is 12, what is the total surface area of this prism?

Check the picture below.

let's recall that a rhombus diagonals intersect at right-angles and that in a rhombus, slanted as it may be, the sides are all equal.

so we can find the area of one the triangles in the rhombus by simply using a base of 3 and a height of 4, and since there are four of those triangles, 4 times that much is the area of one of the rhombic faces.

as  you see in the picture, if we use the pythagorean theorem, we end up with a hypotenuse of 5, which is the length of the base sides on this prism, which also has four rectangular faces standing up vertically, each face is a 5x12 rectangle.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).