At 2: 00 pm a car's speedometer reads 30 mi/h. at 2: 20 pm it reads 50 mi/h. show that at some time between 2: 00 and 2: 20 the acceleration is exactly 60 mi/h2.let v(t) be the velocity of the car t hours after 2: 00 pm. then v(1/3) − v(0)/1/3 − 0 = . by the mean value theorem, there is a number c such that 0 < c < with v'(c) = . since v'(t) is the acceleration at time t, the acceleration c hours after 2: 00 pm is exactly 60 mi/h2.

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)

d is the answer

step-by-step explanation:

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours