Suppose f(x)=x^3 find the graph of f(x+4)

  graph 1

Step-by-step explanation:

f(x+4) shifts the graph of f(x) left 4 units. The graph that shows y=x^3 shifted left 4 units is graph 1.

The point (0, f(0)) = (0, 0) is the point of inflection on the curve. In the function f(x+4), the value of x must be -4 in order to get a y-value of 0. That is, the point that was (0, f(0)) now is (-4, f(-4+4)) = (-4, f(0)). It has been moved 4 units to the left.

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4