Ali will rent a car for the weekend. he can choose one of two plans. the first plan has an initial fee of 70 and costs an additional .60 per mile driven. the second plan has no initial fee but costs .80 per mile driven. how many miles would ali need to drive for the two plans to cost the same?

Ali would need to drive 350 miles for the two plans to cost the same.

Step-by-step explanation:

This question can be solved by creating two equations using the information supplied in the question and then solving these simultaneously.

Let the cost be C.

Let the number of miles be M.

Let the initial payment be i.

Let the rate per mile driven be R.

Plan 1:

C = i+R×M

C = 70+0.60M ... equation 1

Plan 2:

C = i+R×M

C = 0+0.80M

C = 0.80M ...equation 2

Substituting equation 2 into equation 1:

0.80M = 70+0.60M

0.80-0.60M = 70

0.20M = 70

M = 70/0.20

M = 350 miles

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.