(6) aidan has 6 (different) bulls and 10 (different) horses living at his animal sanctuary he needs to place them in a line of 16 paddocks and the bulls cannot be placed in adjacent paddocks (otherwise they will try to fight one another). how many ways can aiden place the bulls and horses in the paddocks so that no two bulls are in adjacent paddocks? (hint: first arrange the horses, then consider possible places for the bulls a paddock is an enclosure where a large animal lives

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6

answer: i ! the answer is   9000 seconds, also d

hope i

-lavira : )