Julian needs to spend at least seven hours each week practicing the drums. he has already practiced five and one third hours this week. he wants to split the remaining practice time evenly between the last two days of the week. write an inequality to determine the minimum number of hours he needs to practice on each of the two days.
five and one third + 2x ≤ 7
five and one thirdx + 2 ≤ 7
five and one thirdx + 2 ≥ 7
five and one third + 2x ≥ 7

five and one third + 2x ≥ 7

Step-by-step explanation:

Let

x -----> the minimum number of hours he needs to practice on each of the two days

we know that

Julian needs to spend at least seven hours each week practicing the drums

so

Convert mixed number to an improper fraction

substitute

Subtract 16/3 both sides

Divide by 2 both sides

therefore

The minimum number of hours he needs to practice on each of the two days is

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: