There is a class of 63 students. the teacher and each student owns and keeps in his/her pocket a working cell phone. each of these cell phones has a log of the phone number of everyother student. email is down. the teacher will cancel class and needs to let the class know as fast as possible since the class starts in 15 minutes. clearly, the teacher can't call all the students himself; there isn't enough time. write an algorithm for the teacher to follow to expedite informing all students in the class that it is cancelled. note: you are to assume that you are living in 1999 when there was no text messaging and no conference calling, i. e. you can only make one call to one recipient at a time and each call takes exactly 2 minutes.

Use a graph site then you will find your answer

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12