Let a = {2, 4} and b = {1, 3, 5} and define a relation u, v and w from a to b as follows: for every (x, y) is in a ✕ b, every (x, y) is in u means thay y - x > 2. every (x, y) is in v means thay y - 1 = x/2. w = {(2, 5), (4, 1), (2, 3)}. (a) draw arrow diagrams for u, v and w (b) indicate whether any of the relations u, v, and w are functions.

Given,

A = {2,4},

B = {1, 3, 5}

U, V and W are the relation from A and B as follow,

U = { (x,y) : y - x > 2, x∈A, y∈B }

V = { (x,y) : y - 1 = x/2, x∈A, y∈B }

W = {(2, 5), (4, 1), (2, 3)},

∵ 1-2 = -1, 1-4 = -3, 3-2 = 1, 3-4 = -1, 5-2 = 3, 5 - 4 =1,

Thus, U = { (2,5) },

Also, 1 - 1 = 0, 3 - 1 = 2, 5 - 1 = 4

∵

⇒ V = { (4,3) }

(a) Drawing is shown below,

(b) Since, a relation is called function if each input has only one output,

Hence, U and V are functions while W is not the function.

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!