When you compare the numbers on the left, you need to look at the ones digits. when you compare the numbers on the right, you do not need to compare the ones digits. explain. 5,278 5,272 5,398 5,353

Same digits till the ones digits

Same digits till tens digits

Step-by-step explanation:

* Lets explain how to solve the problem

- The numbers on the left are 5,278 and 5,272

- When we compare any to numbers with the same number of digits

  we must start from the leftmost digit and go to the right

∵ The two numbers have 4 digits ⇒ thousands - hundreds - tens - one

∵ The leftmost digits in the 2 numbers (thousands) are equal

∵ The hundreds digits of the 2 number are equal

∵ The tens digits of the 2 number are equal

∴ We must to look at the ones digits to compare between them

∴ We need to look at the ones digits

- The numbers on the right are 5398 and 5353

∵ The two numbers have the thousands digits

∵ The two numbers have the same hundred digits

∵ The two numbers not having the same tens digits

∴ We compare between them using the tens digits not the

   ones digits

∴ We do not need to compare the ones digits

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

{3 + i, 3 - i, 3, -1}

step-by-step explanation: