Airplane a traveled 1273 miles in four hours. for airplane b, y =
621
2
x represents its rate of speed over the same four hours. which airplane traveled at a faster rate and by what factor? (round to nearest hundredth)
a) airplane b by a factor of 7.75
b) airplane a by a factor of 7.75
c) airplane b by a factor of 1.02
d) airplane a by a factor of 1.02

D) Train A by a factor of 1.1

Train A: 17/35 = 34.6

Train B: Rate is the slope of the equation, 31.35

Thus,34.6/31.35 = 1.1036

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

597

step-by-step explanation: