Arectangle has a length of x+7 and a width of 2x-3. if it’s perimeter is 32, what is the value of 3x? a.4/b.12/c.14/d.36/e.42/

The correct option is C. 14.

Step-by-step explanation:

First you have that the perimeter of a rectangle = (2·length) + (2·width)

⇒perimeter of a rectangle = [2·( x + 7)] + [2·(2x - 3)]

⇒ 32 = [2·( x + 7)] + [2·(2x - 3)] ⇒ 32 = (2x + 14) + (4x - 6)

⇒ 32 = 6x + 8 ⇒ 32 - 8 = 6x ⇒ 24= 6x ⇒ 24/6 = x ⇒ x = 4. ⇒ 3x= 12.

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step-by-step explanation: