Agrocer want to mix two kinds of coffee. one kind sells for $1.15 per pound, and the other sell for $1.40 per pound. he wants to mix a total of 30 pounds and sell for $1.35 per pound. how many pounds of each kind should he use in the new mix? rozier want to mix two kinds of coffee. one kind sell for $1.15 per pound, and the other sell for $1.40 per pound. he wants to mix a total of 30 pounds and sell for $1.35 per pound. how many pounds of each kind should he use in the new mix

24 pounds of 1.35 and 6 pounds of 1.15

Step-by-step explanation:

First you need to be able to write equations:

x: pounds of 1.40 coffee in the mix

y: pounds of 1.15 coffee in the mix

He wants to mix 30 pounds:

x+y= 30

Also the new price will be 1.35:

1.40*x + 1.15*y = 1.35

Replacing y = 30 - x

1.40*x + 1.15(30-x) = 1.35

Solving that you get:

x = 24

y = 6

the answer is d

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph