Recall, we have five connectives in propositional logic a, v, (negation, conjunction, disjunction, conditional and biconditional). in fact, to express every possible outcome we only need the negation and the conditional connectives show how this is done by writing alternative expressions (i. e. logically equivalent ones) for the expressions below, using only the connectives and type or paste your answers in the write submission box. as usual, you may substitute for - and - for, if you're typing answers. a) pa q b) p v q c) p q

20

step-by-step explanation:

what

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.