In high school, some students have been confused to believe that 22/7 is already the actual value of π or an acceptable approximation. show that 355/113 is a better approximation in terms of absolute and relative errors.

Since it has smaller absolute and relative errors, 355/113 is a better aproximation for than 22/7

Step-by-step explanation:

The formula for the absolute error is:

Absolute error = |Actual Value - Measured Value|

The formula for the relative error is:

Relative error = |Absolute error/Actual value|

I am going to consider the actual value of as 3.14159265359.

In the case of 22/7:

22/7 = 3.14285714286.

Absolute error = |3.14159265359 - 3.14285714286| = 0.00126448927

Relative error = 0.00126448927/3.14159265359 = 0.00040249943 = 0.04%

In the case of 355/113

355/113 = 3.14159292035

Absolute error = |3.14159265359 - 3.14159292035| = 0.00000026676

Relative error = 0.00000026676/3.14159265359 = 0.000000085 = 0.0000085%

Since it has smaller absolute and relative errors, 355/113 is a better aproximation for than 22/7

6 meters

step-by-step explanation:

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: