The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the plane of the equator. assuming the earth is a sphere with a radius of 6.38 x 106 m, determine the speed and centripetal acceleration of a person situated (a) at the equator and (b) at a latitude of 30.0° north of the equator.

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = meters per second squared

Step-by-step explanation:

The formula is:

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

Centripetal Acceleration at Equator = meters per second squared

b)

At 30.0° north of the equator:

Now,

Speed =

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

Centripetal Acceleration at 30 degrees north of equator = meters per second squared

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )