Afootball player kicks a football downfield. the height of the football increases until it reaches a maximum height of 15 yards, 30 yards away from the player. a second kick is modeled by $f\left(x\right)=-0.032x\left(x-50\ right)$ , where $f$ is the height (in yards) and $x$ is the horizontal distance (in yards). compare the distances that the footballs travel before hitting the ground.

kick 1 has travelled 15 + 15 = 30 yards before hitting the ground

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards  

Step-by-step explanation:

1st kick travelled 15 yards to reach maximum height of 8 yards

so, it has travelled 15 + 15 = 30 yards before hitting the ground

2nd kick is given by the equation

y (x) = -0.032x(x - 50)

we know that maximum height occurs is given as

and maximum height is

y = 20

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards  

idk this answer sorry cant on this one.

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: