Write the point-slope form of the line that passes through (-8,2) and is perpendicular to a line with a slope of -8 include all of your work in your final answer.

The point-slope form of the line that passes through (-8,2) and is perpendicular to a line with a slope of -8 is x -8y +24 = 0

Solution:

The point slope form of the line that passes through the points and perpendicular to the line with a slope of “m” is given as  

  ---- eqn 1

Where “m” is the slope of the line. are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope -8 can be found out.

On cross multiplying we get,

8y - 16 = (x+8)

8y – 16 = x +8

On rearranging we get,

x -8y +16 + 8 = 0

x -8y +24 = 0

hence the point slope form of given line is x -8y +24 = 0

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

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