Suppose we have four coins and possibly one coin is either too light or too heavy (all four might be true). (a) show how to determine which of the nine possible situations holds with just two weighings, if given one additional coin known to be true. (b) show that two weighings are not sufficient without the extra true coin

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

dont know

step-by-step explanation:

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors