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write each equation in slope-intercept form of the equation of a line. underline the slope and circle the y-intercept in each equation.

3x+4y–12=0

2x+y=1

2x–y=0

Step-by-step explanation:

Slope intercept form is y=mx+c

1)3x+4y=12

 4y=12-3x

 y = 12/4 - (3/4)x

 y =3-(3/4)x

Slope = -3/4

y-intercept = 3

2) 2x+y=1

   y = 1-2x

   Slope = -2

   y-intercept = 1

3) 2x–y=0

   y = 2x

  Slope = 2

  It doesn't have a y-intercept

true

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.