Three consecutive even integers have a sum of 18. find the integers.

Let
x = first consecutive even
x + 2 = second consecutive even
x + 4 = third consecutive even

Based on the problem, we equate
x + (x + 2) + (x + 4) = 18
Solving for x,
3x + 6 = 18
3x = 18 - 6
3x = 12
x = 12/3
x = 4
and x + 2 = 4 + 2 = 6
and x + 4 = 4 + 4 = 8

Therefore, the three consecutive even integers are 4, 6, 8.

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