Tameka bought 50 cans of soda ( cola, grape, and orange) to serve at a party. she has 8 more colas than grape sodas, and 3 less orange sodas than grape sodas. how many of each type of soda did tameka buy?

Orange = 12

Grape = 15

Cola = 23

Step-by-step explanation:

Turning this into equations you can give each soda a variable

Cola = C | Grape = G | Orange = R

Then you get:

8 + G = C

R + 3 = G

C + G + R = 50

We want to get a variable all by itself in an equation so first I'm going to put the second equation (R + 3 = G) in the first (8 + G = C) by replacing the G to get

8 + (R + 3) = C  Combine the variables 11 + R = C and put that new equation into the last equation

(11 + R) + G + R = 50    

Now plug our original second equation (R + 3 = G) into our third to get

(11 + R) + (R + 3) + R = 50    

Combine and get

14 + 3R = 50      Subtract over the 14

3R = 36              Divide by 3

Orange Sodas = 12

Our new 3rd Equation is now:   C + G + 12 = 50, subtract over 12 to get

C + G = 38

Plug either equation 1 or 2 into that one, I'll do 1

(8 + G) + G = 38

8 + 2G = 38

2G = 30

Grape Sodas = 15

Now our 3rd equation is C + 15 = 38, subtract over 15

Cola Sodas = 23

Orange = 12

Grape = 15

Cola = 23

12 + 15 + 23 = 50

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following